I went to a Pop Will Eat Itself concert recently, and for the first time had a reason to test out the video-recording abilities of the new camera. Given the camera's minimal dimensions and tiny lens, I wasn't expecting great results. However, despite the gloominess of the venue, I was (mostly) pleasantly surprised by the results!
As you can see, the picture quality was fairly good. I had the camera set to record at the maximum settings (320x240 resolution, 30fps). Watching it on the camera was fairly uninspiring, but once I had copied it over to my Mac the apparent quality improved dramatically.
I was however surprised by the size of the video clip. A 2 minute 30 second clip recorded on the camera turned out to be 86.5MB in size. I was curious as to why it was so huge, so I set about doing some investigation. Opening the file in QuickTime Player revealed that the video component was recorded in the Photo-JPEG format! I can only presume that the limited CPU power of the camera limits it to recording in largely uncompressed video and totally uncompressed audio.
The actual settings were:
Photo JPEG video, 320x240, 4700 kbps (!!!!)
PCM audio, 8 bit, mono, 7875Hz, 60 kbps
I wanted to save the clip, but in a more efficient way. I also wanted to contrast it to a more modern way of storing video, so I fired up ffmpegX and ran a few conversions:
Converting the clip to an xvid/mp3 of equal dimensions and very similar visual quality resulted in a 10.6MB file comprising an 8.1MB 320x240 30fps 450kbps xvid video stream and a 2.2MB 144kbps mp3 audio stream! Given that 160kbps mp3 is generally considered to be sufficient for virtually CD-quality, you can see how much the Minolta's capabilities could be improved.
Purely out of interest I also used ffmpegX to convert the clip to DVD specifications. My 320x240 86.5MB photo-JPEG clip turned into a 720x480 75.2MB mpeg2 clip. Definitely bloated!